Question

The number of seeds in watermelons from an organic farm follow a distribution that is skewed to the right with a mean of 348 seeds and a standard deviation of 149 seeds. If a farmer randomly selects 50 watermelons from this farm, what is the probability that the average number of seeds is greater than 400 ap statistics

Answer 1

89

Explanation:

Answer 2

The probability that the average number of seeds is greater than 400 is: 0.0068

How to find the probability from the z-score?

The formula to find z-score is;

z = (x - μ)/(s/√n)

Where;

x is sample mean

μ is population mean

s is standard deviation

n is sample size

We are given;

x = 400

μ = 149

s = 159

n = 50

We will assume a 95% confidence level.

Thus;

z = (400 - 149)/(159/√50)

z = 2.47

Using online p-value from z-score calculator, we have;

p-value = 0.0068