Question

You conduct 25 trials where the probability for each is 0.44. Assuming this is a binomial distribution, finding the probability of 15 success

0.123
0.044
0.246
0.560

Answer 1

B. 0.044

Explanation:

Answer 2

0.044

Explanation:

You conduct 25 trials where the probability for each success is 0.44

Probability of each failure = 1- p (succcess)= 1- 0.44= 0.56

Now we use binomial distribution formula

`P(x) = nCx(p)^x * q^(n-x)`

n = number of trials = 25

p= probability of getting success = 0.44

q = probability of failures = 0.56

x = number of success = 15

plug in all the values in the formula

`P(15) = 25C15(0.44)^15 * 0.56^(10)`

`25C15 = (25!)/(151(25-15)!) =3268760`

`P(15) = 3268760(0.44)^15 * 0.56^(10)`

P(15)= 0.0444685995

Answer is 0.044