211k views
5 votes
Bank A offers a saving account with a 6% APR compounded semiannually. Bank B offers the same rate but compounds monthly. If $1000.00 is invested in both banks, find the difference in interest earned at the end of the year.

User IMDroid
by
8.1k points

1 Answer

5 votes

Answer:

$0.78

Explanation:

Here we have to use the formulas.

Compound interest calculate semiannually

A = P(1 + r/2)^2n

Where P = Principal

R = Rate and n = number of years

Here n = 1, r = 6% = 0.06

A = 1000(1 + 0.06/2)^2(1)

= 1000(1 +0.03)^2

= 1000 (1.03)^2

= 1000(1.0609)

A = 1060.9

Compound interest = 1060.9 - 1000

= $60.90

Compound interest calculated monthly

A = P(1 + r/n)^nt

Here is n is the number of times the interested compounded per year, n = 12 and t = number of years

A= 1000(1 + 0.06/12)^12(1)

A= 1000(1 + 0.005)^12

A= 1000(1.005)^12

A= $1061.68

Compound interest calculated monthly (after 1 year) = 1061.68 - 1000

=$61.68

The difference in interest earned at the end of the year = $61.68 - $60.90

= $0.78

Thank you.

User Ahmet Firat Keler
by
8.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories