Question

Given that z is a standard normal random variable, find the value of z for each situation. a. The area to the right of z is 0.01.

Answer 1

Answer: =1.34

Explanation:

In standard density curve

P(Z<z) = Area left of z, P(Z>z) = area right of z.

P(Z<z) +P(Z>z) =1

Given: z is a standard normal random variable.

To find : value of z if rea to the right of z is 0.01.

i.e. P(Z>z) =0.01

P(Z<z) =1-0.01 = 0.09

from z-score table, z value for this is 1.34.

Hence, z= 1.34