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A circle in the xy-plane is centered at (3, 0) and has a radius with endpoint (1, 8/3 ). Which answer choice is an equation of the circle?

User Lanpa
by
8.0k points

1 Answer

7 votes

Answer: (x - 3)² + y² =
(100)/(9)

Explanation:

Circle Formula: (x - h)² + (y - k)² = r² ; (h, k) is the center & r is the radius

Use the distance formula for (3, 0) and (1,
(8)/(3))


r = \sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)}


r = \sqrt{(3-1)^(2)+(0-(8)/(3))^(2)}


r = \sqrt{(2)^(2)+(-(8)/(3))^(2)}


r = \sqrt{4+(64)/(9)}


r = \sqrt{(36)/(9)+(64)/(9)}


r = \sqrt{(100)/(9)}


r = (10)/(3)

****************************************************

Center (h, k) = (3, 0) Radius (r) =
(10)/(3)

(x - h)² + (y - k)² = r²

(x - 3)² + (y - 0)² = (
(10)/(3)

(x - 3)² + y² =
(100)/(9)

User Linens
by
8.4k points

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