Question

East high schools student council plans to buy some stools and chairs for a new student center. They need to buy 25 more chairs than stools. The chairs cost $32 each and the stools cost $28 each. If the budget is $2,620, how many chairs can they buy?

Answer 1

The number of chairs they buy is, 55

Explanation:

Let x be the number of stools buy and y be the number of chairs buy.

As per the given condition : East high school need to buy 25 more chairs than stools.

i.e,

y = x +25 ......[1]

It is given that the chairs cost $32 each and the stools cost $ 28 each and the total budget is $ 2,620 then;

28x+32y = 2620 ......[2]

Substitute equation [1] into [2] we have:

`28x + 32(x+25) = 2620`

using distributive property:
`a \cdot(b+c) = a\cdot b+ a\cdot c`

`28x + 32x +800 = 2620`

Combine like terms:

`60x + 800 = 2620`

Subtract 800 from both sides we have:

`60x + 800 -800 = 2620 -800`

Simplify:

`60x = 1820`

Divide both sides by 60 we have:

`(60x)/(60) =(1820)/(60)`

Simplify:

x = 30.3333...

Since , the stools they buy are are in number so we have , x = 30 stools.

Substitute in equation [1] we have;

y = 30 + 25 = 55

Therefore, the number of chairs they buy is, 55 chairs.