Answer:
(e) CO2 is formed twice as fast as ethane is consumed.
Step-by-step explanation:
Since we have the equation of the reaction as;
2C2H6(g) + 7O2(g) 4CO2(g) + 6H2O(l)
The rate of consumption of ethene = -1/2 d[C2H6]/dt
Rate of production of CO2= 1/4 d[CO2]/dt
Hence, CO2 is formed twice as fast as ethane is consumed.