Answer:
The inequality for the given graph is
.
Explanation:
From the given graph it noticed that the line passing through (0,-1) and (3,1).
The equation of line passing through two points is defined as

The equation of line is



Therefore the related equation is
.
The point (0,0) lies in the shaded region, therefore the point (0,0) is the solution of required inequality.
Put (0,0) in the related equation.


Since 0 is greater than -1, therefore the sign of inequality must be >. The related line is a dotted line, therefore we cannot use
.
Therefore the required inequality is
