Question

before a collision, a 25 kg object is moving to the right at 12 m/s. Find the impulse acted on the object if, after the collision, the object moves to the left at 6.2 m/s

Answer 1

455 kg m/s

Step-by-step explanation:

The impulse acted on the object is equal to the change in momentum of the object:

`I=\Delta p`

and the change in momentum is equal to the product between the mass of the object and the change in velocity:

`\Delta p=m \Delta v=m (v-u)`

where:

m = 25 kg is the mass of the object

u = 12 m/s is the initial velocity of the object

v = -6.2 m/s is the final velocity of the object (we have taken a negative sign because the object now moves in the opposite direction)

Therefore, the impulse is

`I=\Delta p=m(v-u)=(25 kg)(12 m/s-(-6.2 m/s))=455 kg m/s`