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What is the area of the irregular pentagon

a. 43


b. 105



C)

108 in2



D)

114 in2

What is the area of the irregular pentagon a. 43 b. 105 C) 108 in2 D) 114 in2-example-1
User Chendur
by
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2 Answers

4 votes

Answer:

Answer is 105 in^2

Step-by-step explanation:

Area of rectangle= length X breadth = 8X12=96in^ 2Area of triangle= 1/2 X base X height= 1/2 X 3 X 6= 9 in^2 Area of irregular pentagon = area of triangle + area of rectangle = 96+9=105 in ^2

User Nu
by
5.6k points
2 votes

Answer:

Answer is 105 in^2

Step-by-step explanation: Area of rectangle= length X breadth

= 8X12

=96in^ 2

Area of triangle= 1/2 X base X height

= 1/2 X 3 X 6

= 9 in^2

Area of irregular pentagon = area of triangle + area of rectangle

= 96+9

=105 in ^2


User Parker Hoyes
by
5.4k points