Question

find the equation of the straight line passing through the point (0,-1) which is perpendicular to the line y=-3/4x-3

Answer 1

y =
`(4)/(3)` x - 1

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = -
`(3)/(4)` x - 3 is in this form

with slope m = -
`(3)/(4)`

the slope of a perpendicular line is the negative reciprocal of m, hence

`m_(perpendicular)` =
`(4)/(3)`

(0 , - 1 ) is the y-intercept ⇒ c = - 1

y =
`(4)/(3)` x - 1 ← equation of perpendicular line