Question

In this reaction, how does the rate of forward reaction vary with the concentration of the product?

2H2S(g) ⇌ 2H2(g) + S2(g)

A. It increases with an increase in the concentration of S2(g).
B. It decreases with a decrease in the concentration of H2(g).
C. It increases with a decrease in the concentration of H2(g).
D. It decreases with an increase in the concentration of S2(g).
E. It decreases with increase in the concentration of H2(g).

CAN CHOOSE MORE THAN ONE

Answer 1

C. It increases with a decrease in the concentration of H2(g).

D. It decreases with an increase in the concentration of S2(g).

E. It decreases with increase in the concentration of H2(g).

Step-by-step explanation:

- 2021 Edmentum

Answer 2

Answer : The correct options are C, D, E.

Explanation :

According to this Le chatelier's principle, if we are increasing the rate of reaction then the equilibrium of the reaction will shift towards the low concentration side. And, if we are decreasing the rate of reaction then the equilibrium of the reaction will shift towards the high concentration side.

The effect on rate of forward reaction to the concentration of product.

The rate of forward reaction increases when the concentration of product decreases. Or, the rate of forward reaction decreases when the concentration of the product increases.

The effect on rate of forward reaction to the concentration of reactant.

The rate of forward reaction increases when the concentration of reactant increases. Or, the rate of forward reaction decreases when the concentration of the reactant decreases.

Therefore, from the given options, the option C, D, E are the correct.