Question

Find four consecutive integers whose sum is 682

Answer 1

Hi!

We will solve this like this, with the helps of the equation:

x + (x+1) + (x+2) + (x+3) = 682

4x + 6 = 682

4x = 676

x = 676/4

x = 169

The numbers then are: x = 169, x+1 = 170, x+2 = 171 and x+3 = 172

Hope this helps!

Answer 2

169, 170, 171, 172

Explanation:

X+(x+1)+(x+2)+(x+3)=682.

4x+1+2+3=682

4x+6=682

4x=676

X=169