Question

Two jet planes simultaneously started traveling in opposite directions from the same airport. Four hours later they were 3800 miles apart. Find the rate of each plane, if one of them traveled 80 miles per hour faster than the other.

Answer 1

The first plane is 435mph and the second is 515mph

Explanation:

I got it from somewhere else

If the planes mph's are the other way around, sorry!

Answer 2

435 miles per hour, 515 miles per hour

Explanation:

Let us assume that plane A is traveling at 'x' miles per hour, then plane B is traveling at 'x+80' miles per hour. As the question says that one of them traveled 80 miles per hour faster than other.

After 4 hours they were 3800 miles apart.

We know that,

`t= (distance)/(speed)`

Since two planes are traveling in opposite directions, so we will add their speed.

Putting the values in the equation we get,

`4= (3800)/(x+(x+80))`

Now, solving for 'x'

`4(x+(x+80))=3800`

`4x+4x+320=3800`

`8x= 3800-320`

`8x=3480`

`x=(3480)/(8) =435`

So the rate of plane A is 435 miles per hour and the rate of plane B is (435+80 = 515) miles per hour.