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Problem 3. The uniform beam is supported by two rods AB and CD that have cross-sectional areas of 10 mm2 and 15mm2, respectively. Determine the intensity w of the distributed load so that the average normal stress in each rod does not exceed 300 kPa.

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Answer:

hello the diagram related to your question is missing attached below is the required diagram.

The value of AC = 6m

answer 2.25 N

Step-by-step explanation:

From the diagram attached below

average intensity of loading = w/2

Total load due to linearly varying load =
(wL)/(2)

w = maximum intensity of load , L = span of varying load

since AC = 6m( L ) then

Total load due to linearly varying load = 3w ------ ( 1 )

attached below is the detailed solution of the given problem

Problem 3. The uniform beam is supported by two rods AB and CD that have cross-sectional-example-1
Problem 3. The uniform beam is supported by two rods AB and CD that have cross-sectional-example-2
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