Answer:
21 and 26 totaling 47sticks
Explanation:
Th number of sticks form an arithmetic progression
1, 6, 11, 16...
The nth term of an arithmetic progression is expressed as;
Tn = a+(n-1)d
a is the first term = 1
d is the common difference
d = 6-1 = 11-6 = 5
n is the number of terms
The next two terms are the fifth and sixth term
T5 = 1+(5-1)5
T5 = 1+4(5)
T5 = 1+20
T5 = 21
T6 = 1+(6-1)5
T6 = 1+5(5)
T6 = 1+25
T6 = 26
Hence the number of sticks needed in the next two piles are 21 and 26 totaling 47sticks