Question

What is the equation of the line that passes through the point (6,-7) and has a slope of -3/2

Answer 1

The point-slope form:

`y-y_1=m(x-x_1)`

We have the point (6, -7) and a slope m = -3/2. Substitute:

`y-(-7)=-(3)/(2)(x-6)\\\\\boxed{y+7=-(3)/(2)(x-6)}`