Question

The equilibrium constant for the formation of ammonia from nitrogen and hydrogen is 1.6 × 102. what is the form of the equilibrium constant?

Answer 1

Answer: The expression for equilibrium constant is
`([NH_3]^2)/([H_2]^3[N_2])`

Explanation: Equilibrium constant is the expression which relates the concentration of products and reactants preset at equilibrium at constant temperature. It is represented as
`k_c`

For a general reaction:

`aA+bB\rightleftharpoons cC+dD`

The equilibrium constant is written as:

`k_c=([C]^c[D]^d)/([A]^a[B]^b)`

Chemical reaction for the formation of ammonia is:

`N_2+3H_3\rightleftharpoons 2NH_3`

`k_c=1.6* 10^2`

Expression for
`k_c` is:

`k_c=([NH_3]^2)/([H_2]^3[N_2])`

`1.6* 10^2=([NH_3]^2)/([H_2]^3[N_2])`