Question

A calorimeter contains 195 g of water at 20.4 º C. A 37.8 g sample of an unknown metal is heated to 133 º C and placed into the water in the calorimeter. The final temperature of the metal and the water are 24.6 º C. What is the specific heat of the metal?

Answer 1

To determine the specific heat of the metal, we can use the equation: qm = -qw, where qm is the heat gained by the metal and qw is the heat lost by the water. The heat gained by the metal can be determined using the equation: qm = mcΔTm, where m is the mass of the metal, c is the specific heat capacity of the metal, and ΔTm is the change in temperature of the metal. The heat lost by the water can be determined using the equation: qw = mcΔTw, where m is the mass of the water, c is the specific heat capacity of water, and ΔTw is the change in temperature of the water. By substituting the given values into these equations and rearranging for c, we can determine the specific heat of the metal.

Step-by-step explanation:

To determine the specific heat of the metal, we can use the equation:

qm = -qw

Where qm is the heat gained by the metal and qw is the heat lost by the water. The heat gained by the metal can be determined using the equation:

qm = mcΔTm

Where m is the mass of the metal, c is the specific heat capacity of the metal, and ΔTm is the change in temperature of the metal. The heat lost by the water can be determined using the equation:

qw = mcΔTw

Where m is the mass of the water, c is the specific heat capacity of water, and ΔTw is the change in temperature of the water. By substituting the given values into these equations and rearranging for c, we can determine the specific heat of the metal.

Answer 2

heat loss by the sample=heat gain by the water

Q=mass(kg)*Specific heat* Change in temperature

=m*c*Change in T

0.0378*c*(24.6-133)*(-1)=0.195*4186*(24.6-20.4)

c=(0.195*4186*4.2)/(0.0378*(133-24.6))

=836.7 J/(kg*Celsius degree)