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Find the equation of the line with slope =-7 and passing through (-4,-5) .write your equation in point slope and slope intercept forms

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Point-slope form:

y - y₁ = m(x - x₁) "m" is the slope


You know:

m = -7

(-4 , -5) = (x₁ , y₁)

Plug these into the equation:

y - y₁ = m(x - x₁)

y - (-5) = -7(x - (-4))

y + 5 = -7(x + 4)



Slope-intercept form:

y = mx + b "m" is the slope, "b" is the y-intercept (the y value when x = 0)


You can solve this two ways:


#1: Since you know m = -7, plug it into the equation

y = mx + b

y = -7x + b

To find "b", plug in the point (-4, -5) into the equation

y = -7x + b

-5 = -7(-4) + b

-5 = 28 + b Subtract 28 on both sides

-33 = b


y = -7x - 33



#2: Use the point-slope form and change it to slope-intercept form by isolating/getting "y" by itself.

y + 5 = -7(x + 4) First distribute/multiply -7 into (x + 4)

y + 5 = -7x - 28 Subtract 5 on both sides

y = -7x - 33

User Jeremy Holt
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