Question

How many moles of h2o are equivalent to 97.3 grams of h20

Answer 1

Answer : 5.405 moles of
`H_2O` are equivalent to 97.3 grams of
`H_2O`

Solution : Given,

Mass of
`H_2O` = 97.3 g

Molar mass of
`H_2O` = 18 g/mole

Formula used :

`\text{ Number of moles}=\frac{\text{ Given mass}}{\text{ Molar mass}}`

or,

`\text{ Number of moles of }H_2O=\frac{\text{ Given mass of }H_2O}{\text{ Molar mass of }H_2O}`

Now put all the given values in this formula, we get the moles of
`H_2O`

`\text{ Number of moles of }H_2O=(97.3g)/(18g/mole)=5.405moles`

Therefore, 5.405 moles of
`H_2O` are equivalent to 97.3 grams of
`H_2O`