Question

Find the margin of error if p = 65% and n = 500. Round to four decimal places.

0.0427

0.0926

0.0009

0.0414

Answer 1

Option D is correct

Margin of error(to four decimal places) = 0.0414

Explanation:

Given: p = 65% = 0.65 and n = 500

Error of margin (E) is given by:

`E = z^*\sqrt{(p(1-p))/(n)}`

For a confidence level of 95%,

`z^* = 1.96`

Substitute the value of
`z^*` , p and n in the above formula to calculate error of margin (E) :

`E = 1.96 \cdot \sqrt{(0.65(1-0.65))/(500)}`

Simplify:

E = 0.0414082288551

Therefore, the margin of error(round to four decimal places) = 0.0414