Question

A car accelerates for 5 seconds at 2.1 m/s squared if the car initially had a speed of 10 m/s what is its new speed?

Answer 1

D. 20.5 m/s (Works For Apex)

Step-by-step explanation:

You start with the fact that we are already at 10m/s^2 or our initial velocity is 10m/s^2. Then you add the acceleration which is 2.1 m/s^2 for 5 seconds giving us 10.5 m/s^2. 10m/s + 10.5m/s = 20.5m/s

Answer 2

Note that velocity is measured in meters per second (m/s) and acceleration is in meters per second squared (
`(m)/(s^2)`)

Our initial velocity is 10 m/s and then the car accelerated for 5 seconds at 2.1
`(m)/(s^2)`\\

Note that
`a=(velocity)/(time) \\v=acceleration * time\\v=(2.1(m)/(s^2))*(5s)\\ v=10.5 (m)/(s)\\`

So our final velocity is our initial velocity + a*t;

`v = (10+10.5)(m)/(s) \\v=20.5(m)/(s)`