Question

HELP PLEASE ASAP!!! 50 points

Answer 1

(a+b,c)

Explanation:

Note that the midpoint formula is:

`((x_(1) +x_(2))/(2), (y_(1) +y_(2))/(2))`

Point A (0,0) and Point C (2a+2b,2c)

It follows that:

`(((2a+2b +0)/(2), (2c+0)/(2))\\(((2(a+b))/(2), (2c)/(2))\\\\(a+b,c)`

Answer 2

`\text{The formula of a midpoint:}\\\\\left((x_1+x_2)/(2);\ (y_1+y_2)/(2)\right)\\\\\text{We have}\ A(0,\ 0)\ \text{and}\ C(2a+2b,\ 2c).\\\\\text{Substitute:}\\\\x=(0+2a+2b)/(2)=(2a)/(2)+(2b)/(2)=a+b\\\\y=(0+2c)/(2)=(2c)/(2)=c\\\\Answer:\ \boxed{c.\ (a+b,\ c)}`