Question

What is the equation of a line, in point-slope form, that passes through (−4, 1) and has a slope of (5,7) ?

y−1=56(x+8)
y+1=56(x−8)
y+8=56(x−1)
y−8=56(x+1)

Answer 1

y-1=2/3(x+4)

Explanation:

the other ans has a typo @ its last step but right everything else

it is not one of ur choices

the nearest is y−1=56(x+8) as it has the term "y-1"

Answer 2

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

the point-slope form:

`y-y_1=m(x-x_1)`

We have the points (-4, 1) and (5, 7). Substitute:

`m=(7-1)/(5-(-4))=(6)/(9)=(2)/(3)\\\\y-1=(2)/(3)(x-(-4))\\\\\boxed{y-1=\dfra{2}{3}(x+4)}`