Question

What is an equation of the line that passes through the points (8, -7) and
(-6, -7)?

Answer 1

`(\stackrel{x_1}{8}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-6}~,~\stackrel{y_2}{-7}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-7}-\stackrel{y1}{(-7)}}}{\underset{run} {\underset{x_2}{-6}-\underset{x_1}{8}}} \implies \cfrac{-7 +7}{-14} \implies \cfrac{ 0 }{ -14 }\implies 0`

`\begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{0}(x-\stackrel{x_1}{8}) \implies y +7= 0 (x -8) \\\\\\ y+7=0\implies {\LARGE \begin{array}{llll} y=-7 \end{array}}`