Answer:
Answer choice 4. 577 pounds
Explanation:
Given a cylindrical steel post with dimensions:
- Radius = half of diameter = 0.5 * 6 = 3 inches [converting to feet, we need to divide inches by 12, so we have
feet ]
Volume of a cylinder is given as:
Volume =

Substituting all the given values we have:
cubic feet
Since, 1 cubic foot of steel weights 490, 1.1775 cubic foot of steel would weigh

Rounding to nearest pound, we would get
pounds as the answer.
Answer choice 4 is correct.