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Find the volume and solve the application. A steel post is 6 ft. long and 6” thick in diameter. If a cubic foot of steel weighs 490 lb., how much does the rod weigh (to the nearest pound)?

1.) 138
2.) 332
3.) 338
4.) 577

User Metehan
by
8.6k points

2 Answers

3 votes

Answer:

577

Explanation:

User Mms
by
7.9k points
3 votes

Answer:

Answer choice 4. 577 pounds


Explanation:

Given a cylindrical steel post with dimensions:

  • length/height = 6 ft
  • Radius = half of diameter = 0.5 * 6 = 3 inches [converting to feet, we need to divide inches by 12, so we have
    (3)/(12)=0.25 feet ]

Volume of a cylinder is given as:

Volume =
\pi r^(2)h

Substituting all the given values we have:


V=\pi r^(2)h\\V=\pi(0.25)^(2)(6)\\V=0.375\pi\\V=0.375(3.14)\\V=1.1775 cubic feet


Since, 1 cubic foot of steel weights 490, 1.1775 cubic foot of steel would weigh
490*1.1775=576.97

Rounding to nearest pound, we would get
577 pounds as the answer.

Answer choice 4 is correct.

User MarkusQ
by
8.1k points
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