Question

Geometry, finding angle

Answer 1

Check the picture below.

`tan(A)=\cfrac{\stackrel{opposite}{55}}{\underset{adjacent}{48}}\implies A=tan^(-1)\left( \cfrac{55}{48} \right)\implies A\approx 48.9^o \\\\\\ tan(B)=\cfrac{\stackrel{opposite}{48}}{\underset{adjacent}{55}}\implies B=tan^(-1)\left( \cfrac{48}{55} \right)\implies B\approx 41.1^o`

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