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Y=-x^2+20x-64 what is the max height

User KrauseFx
by
7.6k points

1 Answer

1 vote

Answer:

36

Explanation:

The maximum height is the y-coordinate of the vertex

given a quadratic in standard form : ax² + bx + c : a ≠ 0

then the x-coordinate of the vertex is


x_(vertex) = -
(b)/(2a)

y = - x² + 20x - 64 is in standard form

with a = - 1, b = 20 and c = - 64, hence


x_(vertex) = -
(20)/(-2) = 10

substitute x = 10 into the equation for y

y = - (10)² + 20(10) - 64 = 36 ← max height


User Shady Xu
by
7.7k points

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