Question

F 38.7 grams of lithium chlorate decomposes, how many grams of oxygen gas can be produced? 2LiClO3 ? 2LiCl + 3O2 41.1 g O2 20.6 O2 9.13 g O2 6.85 g O2

Answer 1

The grams of oxygen gas that can be produced is 20.6 grams of O₂

calculation

2LiClO₃ → 2 LiCl + 3 O₂

step 1: find the moles of LiClO₃

moles = mass÷ molar mass

from periodic table the molar mass of LiClO₃ =6.9 +35.5 +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281 moles

step 2: use the mole ratio to calculate the moles of O2

from equation above, LiClO₃:O₂ is 2:3

therefore the moles of O₂=0.4281 moles x3/2 =0.6422 moles

Step 3: find mass of O₂

mass= moles x molar mass

from periodic table the molar mass of O₂ = 16 x2= 32 g/mol

mass=0.6422 moles x 32 g/mol = 20.6 grams of O₂