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Let $P$ be the set of $42^{\text{nd}}$ roots of unity, and let $Q$ be the set of $70^{\text{th}}$ roots of unity. How many elements do $P$ and $Q$ have in common

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Answer:

The answer to the given question can be defined as follows:

Explanation:


\to GCF(42, 70) = 7

Therefore, the common roots of unity were


\to e^{\pm i 2\pi (k)/(7)}\\\\\ where \\ \\ k=0,1,...... 6

That's why the answer is 14 for these

User Ruy Rocha
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