Y = x ^(2) - 6x + 9 How do you convert this to vertex form?

Question

`y = x ^(2) - 6x + 9`
How do you convert this to vertex form?

Answer 1

y = (x-3)^2

rewrite to make it match the form

y = 1*(x-3)^2 +0

Explanation:

vertex form: a(x-h)^2 +k

where (h,k) is the vertex

y= x^2 -6x+9

factor

y = (x-3)^2

rewrite to make it match the form

y = 1*(x-3)^2 +0

h=3

k=0

I don't know if they want they 1 and the zero included in your answer