Question

If a car’s speed is 70 miles per hour on a road surface with a drag factor of 0.50 and with a breaking efficiency of 85% (n = .85), what would be the length of the skid marks? Round to the nearest tenth.

Answer 1

About 384.3 feet

Explanation:

The formula for that is given by,

`S= √(30 * d * f * n)`

Where,

S is the speed of the car

d is the distance of skid

f is the drag factor for the road surface

n is breaking efficiency as percentage

Putting the values we get,

`S^2=  30 * d * f * n`

`d= (S^2)/(30 * f * n)`

`d = (70^2)/(30 * 0.50 * 0.85) = 384.3` feet

So the length of skid marks would be 384.3 feet.