Answer:
Option B: a1= 15 ,
![a_n = 2a_(n-1)- 4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/z36ejugll4155vzkr2ep8jjas9a4ftohjn.png)
Explanation:
Given sequence is 15, 26, 48, 92, 180..........
First term is a1, so a1= 15
To get second term 26, we multiply the first term with 2
So it becomes 15*2 = 30
Then we subtract 4 from 30. so 30-4=26
To get third term 48,
previous term 26 *2 - 4= 52-4=48
a_n is the first term and a_(n-1) is the previous term
To get recursive formula
multiply the previous term by 2 and then subtract 4
So recursive formula becomes
![a_n = 2a_(n-1)- 4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/z36ejugll4155vzkr2ep8jjas9a4ftohjn.png)
Option B is correct