Answer:
triangle ABE ≈ triangle CDE using SAS theorem
Explanation:
E is the midpoint of segment BD
So BE = ED and AE = EC
and <BEA = < CED (vertial angles are equal)
so triangle ABE ≈ triangle CDE using SAS theorem
Therefore, by SAS theorem ΔAEB ≅ DEC
In the figure attached
AE = EC [ E is the midpoint of AC]
BE = ED [ E is the midpoint of BD]
and ∠AEB = ∠CED [ vertically opposite angles]
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