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Which of the following operations will change the solution of the system x − y = 2 and 3x − 3y = 2? multiply the first equation by 2 replace the first equation with the sum of x − y = 2 and 3x − 3y = 2 divide the second equation by 3 none of the above

2 Answers

5 votes

Answer:

D.

Explanation:

None of the above

got the right answer

User Guicara
by
8.1k points
5 votes

Answer:

D) none of the above

Explanation:

Given system of equation is x − y = 2 and 3x − 3y = 2

And there are four choices

A) multiply the first equation by 2

B) replace the first equation with the sum of x − y = 2 and 3x − 3y = 2

C) divide the second equation by 3

D) none of the above


Now we need to find about which of the following operations will change the solution of the system x − y = 2 and 3x − 3y = 2?


We know that adding or subtracting or multiplying or dividing same thing on both sides of equation doesn't change the solution so A, C are not possible.

B) says to replace given equations by itself so that will also not change the solution

Hence correct choice will be D.


User Ardget
by
9.2k points