Question

Which of the following is the correct equation for the reaction below?

One molecule of propane gas reacts with five molecules of oxygen gas to form three molecules of carbon dioxide gas and four molecules of water vapor.
A. CzHg (g) + 502 (9) ► 3C02 (9) + 4H20 (9)
B. C3Hg (s) + 502 (s) — 3CO2 (s) + 4H20 (3)
C. CH (9) + 502 (9) — 3C02 (9) + 4HO (9) D. CzHg (9) + 50 (g) → 3C0 (g) + 4H20 (9)

need asap​

Answer 1

C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g)

Step-by-step explanation:

This is the actual answer

Answer 2

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Step-by-step explanation:

One molecule of propane gas reacts with five molecules of oxygen gas to form three molecules of carbon dioxide gas and four molecules of water vapor.

To every chemical equation, there are products and reactants:

Reactants → Products

Here:

Reactants:

1 mole of propane = C₃H₈

5 mole of oxygen gas = 5O₂

Products;

3 mole of CO₂ = 3CO₂

4 moles of water vapor = 4H₂O

The reaction equation is therefore;

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O