Question

Solve for x: x2-14x+49

Answer 1

`\displaystyle\\x^2-14x+49=0\\\\x_(1,2)=(-b\pm√(b^2-4ac))/(2a)=(14\pm√(196-4\cdot49))/(2)= (14\pm√(196-196))/(2)=(14)/(2)=7\\ \\\boxed{x_1=x_2=7}`

Answer 2

x2 − 14x + 49 = 0

Explanation: