Question

What is the standard form of the equation of the parabola shown in the graph?

Answer 1

Answer: its a

Explanation:

i got it right

Answer 2

Answer:
`x^2=-16y`

Explanation:

Since, the standard form of a parabola which is along to the y-axis,

`y=a(x-h)^2+k^2`

Where (h,k) is the vertex of the parabola,

By the given diagram,

The vertex of the parabola along to the y-axis = (0,0)

⇒ h = 0, k=0

By substituting these values in the above equation,

We get,

`y=a(x-0)^2+0`

`\implies y = ax^2` --------(1)

Now, again by the given diagram the parabola is passing through the point (-4,-1),

⇒ This point will be satisfy the equation of parabola,

⇒
`-1 = a(-4)^2`

⇒
`-1 = 16a`

⇒
`(-1)/(16)=a`

By substituting this value in equation (1),

We get,

`y=(-1)/(16)x^2`

`\implies -16 y = x^2`

Which is the required equation of the given parabola.

⇒ First option is correct.