Question

If the , points on the graphs are (-4,1) and (2,1) what is the equation ?

Answer 1

`y=0x+1`, or
`y=1`

Explanation:

The equation will be in slope intercept form.
`y=mx+b`

I can find the slope using the formula:

`(y_2-y_1)/(x_2-x_1)`

When I plug in:
`(1-1)/(2-(-4))`, I find that the slope is 0.

I can then lug in what I know into
`y=mx+b`:

Using (2, 1):

1=0(2)+b. Solving for be I get: b=1

You then get your answer after you plug back in.

Hope this helps!!

Answer 2

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept

To find "m", you can use the slope formula and plug in the two points:

`m=(y_(2)-y_(1))/(x_(2)-x_(1))`

`m=(1-1)/(2-(-4))`

`m=(1-1)/(2+4)`

`m=(0)/(6)=0`

The slope is 0 so:

y = mx + b

y = 0x + b [any number multiplied by 0 is 0]

y = b

To find "b", you plug in either of the points into the equation (since both of their y values are 1]

y = b

1 = b

Your equation is:

y = 1 (This is a horizontal line)