6.9k views
0 votes
QUESTIONS HELP ME PLEASE...

QUESTIONS HELP ME PLEASE...-example-1
QUESTIONS HELP ME PLEASE...-example-1
QUESTIONS HELP ME PLEASE...-example-2
User Smnd
by
8.1k points

1 Answer

3 votes

y = A sin (Bx)

Period: starts at 0 and restarts at 4π

Period = 4π

Period =
(2\pi)/(B)

4π =
(2\pi)/(B)

B =
(2\pi)/(4\pi)

B =
(1)/(2)

A = amplitude. The minimum is -3 and the maximum is +3.

A =
(3 - (-3))/(2)

A =
(6)/(2)

A = 3

y = A sin (Bx)

↓ ↓

y = 3 sin (
(1)/(2)x)

*******************************************************

sin is an odd function so f(x) = -f(x)

Answer: y =
-(1)/(2) (sin 2πx)

form is: y = A sin (Bx) ; where A is the amplitude so,

Amplitude (A) = (
(1)/(2))

The range is between -1/2 and +1/2 so,

Range = [
-(1)/(2) ,
(1)/(2)]

Period =
(2\pi)/(B)

Period =
(2\pi)/(|-2\pi|)

Period = 1

y =
(1)/(2) sin (-2πx)

x=0 ⇒ y =
(1)/(2) sin(-2π(0))

=
(1)/(2) sin(0)

=
(1)/(2) (0)

= 0

(0, 0) works!

x=
(\pi)/(2) ⇒ y =
(1)/(2) sin(-2π(
(\pi)/(2)))

=
(1)/(2) sin(-π²)

=
(1)/(2) (0.17)

= 0.085

(
(\pi)/(2), 1) does NOT work

see attachment for the rest of the points:

(π, 0) does NOT work


((3\pi)/(2), -1) does NOT work

(2π, 0) does NOT work

Graph: D


QUESTIONS HELP ME PLEASE...-example-1
User Rodrigo Almeida
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories