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List the first five terms of the sequence

List the first five terms of the sequence-example-1

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Answer:

a1= 3/2

a2=9/5

a3=27/10

a4=81/17

a5=243/26

Explanation:

Fisrt: an = a1

Formula = (3^n)/(n^2+1)

Replace n by 1 and then continue for a2, a3, a4, a5

Therefore:

a1=(3^1)/(1^2+1) = 3/(1*1+1) = 3/(1+1) = 3/2

a2=(3^2)/(2^2+1) = 9/(4+1) = 9/5

a3 = (3^3)/(3^2+1) = 27/(9+1) = 27/10

a4 = (3^4)/(4^2+1) = 81/(16+1) = 81/17

a5 = (3^5)/(5^2+1) = 243/(25+1) = 243/26

User Mukund Gandlur
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