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How do you solve 12+5x = 18+3x

2 Answers

3 votes

Answer:

x=3

Explanation:

First, get your variables and constants separated on either side of the =

Whatever you do to one side, you have to do to the other.

12 + 5x = 18 + 3x

subtract 3x from both sides to cancel out the 3x on the right:

12 + 5x - 3x = 18 + 3x - 3x

12 + 2x = 18

subtract 12 from both sides to cancel out the 12 on the left side:

12 - 12 + 2x = 18 - 12

now just solve for x

2x = 6

divide both sides by 2 to cancel out the 2 on the left side:

2x / 2 = 6 / 2

x = 3

User Prunge
by
8.0k points
2 votes

Answer: x = 3


Step-by-step explanation:Simplifying

12 + 5x = 18 + 3x

Solving

12 + 5x = 18 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

12 + 5x + -3x = 18 + 3x + -3x

Combine like terms: 5x + -3x = 2x

12 + 2x = 18 + 3x + -3x

Combine like terms: 3x + -3x = 0

12 + 2x = 18 + 0

12 + 2x = 18

Add '-12' to each side of the equation.

12 + -12 + 2x = 18 + -12

Combine like terms: 12 + -12 = 0

0 + 2x = 18 + -12

2x = 18 + -12

Combine like terms: 18 + -12 = 6

2x = 6

Divide each side by '2'.

x = 3

Simplifying

x = 3




User Datentyp
by
7.8k points

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