Question

If an object has a mass of 1417g and it is moved 47 meters in 90 seconds, how much power was used?

Answer 1

Mass of the object is given as

`m = 1417 g = 1.417 kg`

now the speed of object is given as

`v = (d)/(t)`

here we know that

`d = 47 m`

`t = 90 s`

now we will have

`v = (47)/(90) = 0.52 m/s`

now we will have kinetic energy of the object as

`KE = (1)/(2)mv^2`

`KE = (1)/(2)(1.417)(0.52)^2`

`KE = 0.19 J`

now the power is defined as rate of energy

so here we can find power as

`P = (KE)/(t)`

`P = (0.19)/(90) = 2.14* 10^(-3) W`

so above is the power used for the object