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A 2 kg ball attached to a frictionless surface is being spun in a circle of radius 0.5 meters. The string will break when the tension in the string exceeds 16N. How fast can the ball be spinning before the string will break?

User Pumpkin
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1 Answer

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m = mass of the ball attached to friction less surface = 2 kg

r = radius of the circle in which the ball moves = 0.5 meter

T = tension force in the string = 16 N

F = centripetal force

centripetal force is given as

F = m v²/r

the centripetal force required to move in circle is being provided by the tension force here , hence we can write

T = F

T = m v²/r

Tr = m v²

v² = Tr/m

v = √(Tr/m)

inserting the values in the equation above

v = √(16 (0.5)/2)

v = 2 m/s



User Kallja
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