Question

It’s a literal equation and we are solving/isolating H.

H=

PLEASE HELP

Answer 1

h =
`(3v)/(s^(2) )`

Explanation:

v =
`(1)/(3)`
`s^(2)`h You want to isolate the h, so we will do the inverse of dividing by 3, which is multiplying by 3. We will also do the inverse of multiplying by
`s^(2)` which is dividing by
`s^(2)`. We will do this to both sides of the equation. This will cause the
`(1)/(3)` and the
`s^(2)` to cancel out on the right side.

`(v)/(1)` x (
`(3)/(s)^(2) )` =
`(1s^(2)h )/(3)` x
`(3)/(s^(2) )` I put everything as a fraction so it is easier to see what is in the numerator and the denominator.

When when cross cancel and multiply everything out we have:

`(3v)/(s^(2) )` = h