96.0k views
3 votes
What is he range of the function y=2x^2+2 when the domain is (1,3,5)

1 Answer

4 votes

Answer:

range = (4, 20, 52 )

Explanation:

Substitute the given values of x from the domain into the equation and evaluate for y ( the range )

x = 1 : y = 2(1)² + 2 = 2 + 2 = 4

x = 3 : y = 2(3)² + 2 = 18 + 2 = 20

x = 5 : y = 2(5)² + 2 = 50 + 2 = 52

range is y ∈ {4, 20, 52 }



User Vijay Patel
by
8.0k points

No related questions found