Answer:

![2^{(2)/(3)}=\sqrt[3]{2^(2)}](https://img.qammunity.org/2019/formulas/mathematics/high-school/66ud13y4ct804exjwu712r4vljtvs19uib.png)

![3^{(1)/(3)}=\sqrt[3]{3}](https://img.qammunity.org/2019/formulas/mathematics/high-school/2upa56myrxjuysjfbpiqumituj3vl8rf61.png)
Explanation:
First, we need to make some definitions about radical forms.
The expression
is equivalent to :
(I)
Now let's work with the expressions given :
The first one is

Using the expression (I) :
![2^{(1)/(2)}=\sqrt[2]{2^(1)}=√(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/jtdywxjzhhhzdbu6w4lpo4wwgjo89b7ii2.png)
The second one is

Using (I) :
![2^{(2)/(3)}=\sqrt[3]{2^(2)}](https://img.qammunity.org/2019/formulas/mathematics/high-school/66ud13y4ct804exjwu712r4vljtvs19uib.png)
The third expression is

Using the expression (I) :
![3^{(3)/(2)}=\sqrt[2]{3^(3)}=\sqrt{3^(3)}](https://img.qammunity.org/2019/formulas/mathematics/high-school/605qc9p5ycnx50dhi2wdlrk0y4ovt4xiq8.png)
And the last expression is

Using the expression (I) :
![3^{(1)/(3)}=\sqrt[3]{3^(1)}=\sqrt[3]{3}](https://img.qammunity.org/2019/formulas/mathematics/high-school/2kr2w6ucbgnyjbmxwtu5fw4sr80klz26m3.png)