Question

How many atoms make 3.42 moles of zinc (Zn)?

O 2.06 x 1024
65.38
1.76 x 1023
O 6.02 x 1023

Answer 1

Avogadro's number can be used to determine how many atoms are present in 3.42 moles of zinc (Zn). The number of atoms is 2.06 x 10^24 atoms.

Step-by-step explanation:

To find the number of atoms in 3.42 moles of zinc (Zn), we can use Avogadro's number. Avogadro's number, also known as 6.02 x 10^23, represents the number of atoms or molecules in 1 mole of a substance.

First, we need to find the number of atoms in 1 mole of zinc. If 1 mole of zinc has a mass of 65.4 g, then 5 moles of zinc has a mass of 65.4 g x 3.42 mol = 223.908 g.

Next, we can use the molar mass of zinc (65.4 g/mol) and Avogadro's number to calculate the number of atoms in 3.42 moles of zinc:

Number of atoms = 3.42 mol x 6.02 x 10^23 atoms/mol = 2.06 x 10^24 atoms

Answer 2

To obtain one mole of copper atoms (6.02 x 1023 atoms), ... mol Ag? (b) How many atoms of Ag are in 0.0342 mol Ag? 7 ... contain one S atom and two O atoms; calculate its molar mass.