Answer:
Option B is the answer.
Explanation:
To get the equation of the graph we will check all the options given whether they pats through ( 0, 4 ) and (1, 8 )
Option A ⇒ f(x) =

for (0, 4)
f(0) =

for (1, 8 )
f(1) = 4.(8)
= 32 ≠ 8
so incorrect option
Option B ⇒ f(x) =

for (0,4)
f(0) =

= 4
for (1,8) =

= 8 Correct option
Option C ⇒ f(x) =

for (0, 4)
f(0) =

= 2 ≠ 4 Incorrect option
Option D ⇒ f(x) =

for (0, 4)
f(0) =
= 8 ≠ 4 Incorrect option
Option B is the answer.